please help with multiplication and division function

A={1;2;3;4;5;6;7}; B={1;2;3;4;5;6;7};

A and B are both cell arrays, I would like to find C

C=(3*A-C)/2;

Answer 1

[Stephen23]

The solution is simple: don't use cell arrays:

A = [1;2;3;4;5;6;7];
B = [1;2;3;4;5;6;7];
C = (3*A-B)./2;

Answer 2

[Robert U]

Hi Emmanuel Akpan,

The question you raised is not clear. Taking into consideration the given equation you can find easily by manual calculation that it is satisfied for

C = A;

In case you would like to calculate

C = (3*A-B)/2;

while use of cell arrays is mandatory, there are several ways of doing that. Depending on what output format you would like to achieve you might have to alter the shown examples. I assume, output should be cell array again:

A={1;2;3;4;5;6;7};
B={1;2;3;4;5;6;7};

C1 = cellfun(@(cA,cB) (3*cA-cB)/2,A,B,'UniformOutput',false);

C2 = arrayfun(@(dIn) dIn,(3*cell2mat(A)-cell2mat(B))/2,'UniformOutput',false);

Kind regards,

Robert

[Stephen23]

Note that instead of this:

C2 = arrayfun(@(dIn) dIn, ... ,'UniformOutput',false)

to place the elements of a numeric array into the cells of a cell array, just use num2cell:

C2 = num2cell(...)

[Robert U]

True, Thank you Stephen.