regexp split at first whitespace

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I have a cell dataset like this, where it is a string of letters and numbers all in one column (many rows):
data =
'0R 2 2 0'
'1R 2 0 0 4'
'2R 2 2 0 1 1 1'
'3R 2 2 2 1 1'
I would like to split each row into 2 columns at the first space:
data =
'0R' '2 2 0'
'1R' '2 0 0 4'
'2R' '2 2 0 1 1 1'
'3R' '2 2 2 1 1'
I tried:
splitcells = regexp(data, '\s+','split');
but that splits at each space, creating numerous columns, not 2. How do I get the regular expression to split only at the first space? Thanks

Accepted Answer

Paolo
Paolo on 14 Jul 2018
You may use the once option to split only once at the first occurrence of whitespace.
splitcells = regexp(data,'\s','split','once')
  1 Comment
Vincent Scalfani
Vincent Scalfani on 14 Jul 2018
Thanks so much! If anyone else has this question, you can use the following to unnest the 1x2 cells from the split:
data = vertcat(data{:});

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