Saving values from a loop but allocating them to a different index of a vector based on a different value?

Howdy again,

So here is what I'm trying to do. I have a datetime array (format = 'yyyy/MM/dd h:mm:ss a'). I want to obtain the number of counts of events that occur per hour per day as well as per minute per hour per day. But, I want to set up two zeros arrays (one for minutes (zeros(1440,1)) and one for hours (zeros(24,1))) and I want the index of those to represent in the following way:

H = zeros(24,1);
H(1) = counts of events occurring between 00:00:00 and 00:59:00
H(2) = counts of events occurring between 01:00:00 and 01:59:00
.
.
.
H(24) = counts of events occurring between 23:00:00 and 23:59:00

for each new day.

And,

M = zeros(1440,1);
M(1) = counts of events occurring between 00:00:00 and 00:00:59
M(2) = counts of events occurring between 00:01:00 and 00:01:59
.
.
.
M(1440) = counts of events occurring between 23:59:00 and 23:59:59

So the problem is, the dates coming in have different start dates and start times (they are random). So, for sample 1, I might have '2016/05/23 10:46:30 AM', but for sample 2 I might have '2015/12/01 3:12:35 PM'. The datetimes per individual sample are incrementing, and each sample will be run through independently.

I want to store what I'm obtaining into the right index in H and M so that it's representative of how many events occurred across all years, months, and days, in hour 5 of the day or minute 394 of the day or so forth.

This is what I have: (E is a cell array containing the dates and times, G is the datetime array)

% Get counts per minute per day by DOW
    countMinE = zeros(1440,1); % 1440 minutes in a day.  Let index 1 = time 
    % from 00:00:00 until 00:00:59, index 2 = time from 00:01:00 until 00:01:59... 

      countHourE = zeros(24,1); % run for count per hour too

      countMinE(1) = 1;
      countHourE(1) = 1;

      countM = 1;
      countH = 1;
      for i = 1:length(E)-1
         [~,~,d] = ymd(G);
         [h,m,~] = hms(G);
         countM = 1;
         countH = 1;
         if d(i+1) == d(i)
             % same day so check next hour then next minute
             if h(i+1) == h(i)
                 countH = countH+1;
                 countHourE(i+1) = countH;  %%%%This is where I want the value to get stored to the index that the hour is (so if the hour was 13, I'd want a count added to index 13)
                 % same hour, check same minute
                 if m(i+1) == m(i) % another count in same minute, add count
                     countM = countM+1;
                     countMinE(i+1) = countM; %%%%This is where I want the value to get stored to the index that the minute is (so if the minute was 45 and the hour was 3, I'd want a count added to index minutes(hours(3.75)) = 225)
                 else % new minute
                     % do nothing
                 end
             else % new hour
                 % do nothing
             end
         else % new day
             % do nothing
         end
      end

Can anyone help me figure this one out? It's a tough nut to crack for me...

Thanks!