Function handling with derivative of sin

Testing a script to find derivative of f=@sin but Error is coming up every time,I tried to fix it but all efforts got drained .Anyone throw some light

Function itself:

function [finitederivative] = finiteDerivativeApprox(f(x),x)
%Test if function value is able to calculate
%derivative of given assigned values
%f-a handle to function to test
%x-values (scalar or array) to evaluate f at

   [finitederivative] =  (f(x+h) -f(x) )/h;
  end        

*Test script file*

clear
clc
 f=@sin;
 x=pi/3;
 h=1e-6;
 approxDeriv=finiteDerivativeApprox(f,x,);
 fprintf('%.4f\n',approxDeriv);

[Stephen23]

@Shivam kumar: please show us the complete error message. This means all of the red text.

Answer 1

[madhan ravi]

What happens if you try the below code?

f = @(x) sin(x)

x=pi/3

f(x)

Note: Function Handle should be defined inside parentheses

[Walter Roberson]

f = @(x) sin(x)

is just a version of

f = @sin

with more overhead and otherwise the same effect.

[Shivam kumar]

Yes I have tried using @(x)sin(x),still same problem

Answer 2

[Walter Roberson]

function [finitederivative] = finiteDerivativeApprox(f, x, h)
    %Test if function value is able to calculate
    %derivative of given assigned values
    %f-a handle to function to test
    %x-values (scalar or array) to evaluate f at

      [finitederivative] = (f(x+h) -f(x) )/h;
  end

together with

 f = @sin;
 x = pi/3;
 h = 1e-6;
 approxDeriv = finiteDerivativeApprox(f, x, h);
 fprintf('%.4f\n', approxDeriv);