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Question about "min" command.

Asked by Manne Plok on 6 Sep 2018
Latest activity Answered by Greg
on 6 Sep 2018
I have a code that generates the following 2D array:
0 300 7500 10800 76800 86700
36300 30000 10800 7500 7500 10800
300 0 4800 7500 67500 76800
I want to find the row number in which the minimum number in a column is. For example, for column 3, the lowest number is 4800 so the output would be '3'.
However, for column 4, there is a tie (row 2 and 3 both have the lowest number). If I use the min command to generate the rows, it does all of them for me but for column 4 (in the event of a tie), it automatically picks the first one (row 2).
Is there any way for me to keep using min function for this, but adding in some sort of if statement (IDK how I would do that), OR, is there another way for me to find the lowest number per column and give the row output -- a way which tells me there's a tie?

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R2017b

1 Answer

Greg
Answer by Greg
on 6 Sep 2018
 Accepted Answer

One option is to re-compare the first output of min to your original matrix. Then, count how many elements match in each column:
data = [1,2,3,4,5;6,7,8,9,10;11,2,13,14,15];
[minval,minloc] = min(data,[],1);
counts = sum(data==minval,1);
This relies on the implicit expansion feature of R2016b and later. Otherwise, use bsxfun to build the equality comparison to sum.

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