Solution of this Non linear Equation

0.3=0.5*(x-0.022*k^2-5.6)*exp(-0.17*x); find the value of "X" where k=2; Matlab code???

 Accepted Answer

madhan ravi
madhan ravi on 10 Sep 2018
Edited: madhan ravi on 10 Sep 2018
syms x
k=2;
eqn=0.3==0.5*(x-0.022*k^2-5.6)*exp(-0.17*x);
x=vpasolve(eqn)

3 Comments

madhan ravi
madhan ravi on 10 Sep 2018
Edited: madhan ravi on 10 Sep 2018
@Pranjal if it’s working please accept the answer , if not tell what’s not clear?
thanx madhan ravi sir.. for ur help
Your welcome @Pranjal

Sign in to comment.

More Answers (0)

Categories

Find more on Programming in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!