why bitand function is not running even i specified the assumedtype value still error comes
Show older comments
for i = 1:2^samples-2
j = bitset(bitshift(i,1),1,bitget(i,samples)); %rotate left
numt = sum(bitget(bitxor(i,j),1:samples)); %number of 1->0 and 0->1 transitions
if numt == 2 %Uniform pattern
n=sum(bitget(i,1:samples)); %Number of 1-bits
c= bitcmp(j,'uint8');
b=bitand(i,c,'unit64');
r=find(bitget( b,1:samples)); %Rotation index of the bit pattern
r=mod( floor(n/2)+r , samples);
index = (n-1)*samples + r;
table(i+1) = index;
else %Non-uniform
table(i+1) = newMax - 1;
end
end
Here samples=8;
Answers (1)
Walter Roberson
on 13 Sep 2018
0 votes
uint64 not unit64
1 Comment
Guillaume
on 13 Sep 2018
Considering that c is limited to 8 bits, might as well make that uint8 for the bitand as well.
Note that j should be limited to 8 bits prior to the bitcmp otherwise bitcmp will throw an error for larger i (e.g. when i = 207), so:
j = mod(j, 256);
Categories
Find more on Just for fun in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!