How to avoid for-loop here; repmat
    3 views (last 30 days)
  
       Show older comments
    
    Pete sherer
 on 17 Sep 2018
  
    
    
    
    
    Commented: Star Strider
      
      
 on 17 Sep 2018
            Hi Could anyone help suggest a faster way to construct this vector?
xval = [1 2 7 9];
numX = [1 4 2 3];
% I want final output to be [1 2 2 2 2 7 7 9 9 9];
fullX = [];
for runi=1:length( xval)
    tval   = xval( runi);
    n      = numX( runi);
    if n > 0
        fullX= [ fullX; repmat( tval, n, 1)];
    end 
end %
0 Comments
Accepted Answer
More Answers (0)
See Also
Categories
				Find more on Loops and Conditional Statements in Help Center and File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!