access sequence of file with date increment

I have sequence of files name as wrfout_2011-11-01,wrfout_2011-11-02 upto wrfout_2011-12-31 and for 2012 it will start from january wrfout_2012-01-01 to April wrfout_2012-04-30 and then it skip 6 month and then start fron wrfout_2012-11-01 to wrfout_12-12-31,so how can I read this date sequence from sequence of files.

Answer 1

[ANKUR KUMAR]

This answer is not going to specific only for WRF output files, but for all. First read all files and store their names in a variable. And sort if wish.

F=dir('wrfout*')
case_name = reshape({F.name}, [], 1);

If you want only numeric out of file names, then use

dates=cellfun(@(x) char(regexp(x,'\d*','Match')),case_name,'uni',0)

or if you numbers are on the same places in all files, then you can use

dates=cellfun(@(x) strcat(x(8:11),x(13:14),x(16:17)),aa,'uni',0)

If you want to convert into datenum format, then this example may help

A=20180924
a1=num2str(A)
datenum(str2double({a1(1:4),a1(5:6),a1(7:8)})); %for datenum format
A1=[str2double({a1(1:4),a1(5:6),a1(7:8)})] %for storing dates in vector

[shivani badodiya]

i only want to read dates in sequence,which I have given.

Answer 2

[Peter Perkins]

There are other ways to do this, but here's one straight-forward way:

>> dates = [datetime(2011,11,1):caldays(1):datetime(2011,11,3) datetime(2012,1,1):caldays(1):datetime(2012,1,3)]
dates = 
  1×6 datetime array
   01-Nov-2011   02-Nov-2011   03-Nov-2011   01-Jan-2012   02-Jan-2012   03-Jan-2012
>> filenames = string(dates,'''wrfout_''yyyy-MM-dd')
filenames = 
  1×6 string array
  Columns 1 through 5
    "wrfout_2011-11-01"    "wrfout_2011-11-02"    "wrfout_2011-11-03"    "wrfout_2012-01-01"    "wrfout_2012-01-02"
  Column 6
    "wrfout_2012-01-03"