how we can store each and every value in nested for loop.

d=linspace(2,4,3);
for t=1:length(d)
       c(t)=d(t)^2;
    PL=linspace(0.8,1,3);
for q=1:length(PL)
       c1(q,t)=PL(q)^2;
N=linspace(11,13,3);
for y=1:length(N)
    c2(y,q)=N(y)^2;
end
end
end

[madhan ravi]

whats wrong with code?

Answer 1

[KSSV]

d=linspace(2,4,3);
c = zeros([],[]) ; 
c1 = zeros([],[]) ;
c2 = zeros([],[],[]) ;
for t=1:length(d)
    c(t)=d(t)^2;
    PL=linspace(0.8,1,3);
    for q=1:length(PL)
        c1(q,t)=PL(q)^2;
        N=linspace(11,13,3);
        for y=1:length(N)
            c2(y,t,q)=N(y)^2;
        end
    end
end

Answer 2

[KALYAN ACHARJYA]

Here already value stored in each iteration

d=linspace(2,4,3); 
PL=linspace(0.8,1,3);
N=linspace(11,13,3); 
for t=1:length(d) 
    c(t)=d(t)^2; 
    for q=1:length(PL) 
        c1(q,t)=PL(q)^2; 
        for y=1:length(N) 
            c2(y,q)=N(y)^2; 
        end
    end
end

Check result in command window: >> c

c =

     4     9    16

>> c1

c1 =

    0.6400    0.6400    0.6400
    0.8100    0.8100    0.8100
    1.0000    1.0000    1.0000

>> c2

c2 =

   121   121   121
   144   144   144
   169   169   169

>>

[KALYAN ACHARJYA]

For example

              when t=1 c(1)=2^2=4
              when t=2 c(2)=3^2=9
              when t=3 c(3)=4^2=16

Please note you have used

linspace(2,4,3)

ans =

       2     3     4