How to generate numbers from probability mass function?
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Hallo,
Given a probability mass function defined as P(X=3)=0.2, P(X=7)=0.3 and P(X=10)=0.5, I want to generate randomly 30 numbers (values for X) with this probability mass function as base. But I really have no idea how and where to start.
Can somebody help me?
Thank you in advance
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Accepted Answer
  Torsten
      
      
 on 9 Oct 2018
        
      Edited: Torsten
      
      
 on 9 Oct 2018
  
      n = 30;
X = zeros(n,1);
x = rand(n,1);
X(x <= 0.5) = 10;
X(x > 0.5 & x <= 0.8) = 7;
X(x > 0.8) = 3;
3 Comments
  Torsten
      
      
 on 10 Oct 2018
				For an explanation, see
https://stats.stackexchange.com/questions/26858/how-to-generate-numbers-based-on-an-arbitrary-discrete-distribution
More Answers (3)
  Bruno Luong
      
      
 on 9 Oct 2018
        A more generic method:
p = [0.2 0.3 0.5];
v = [3 7 10];
n = 10000;
c = cumsum([0,p(:).']);
c = c/c(end); % make sur the cumulative is 1 
[~,i] = histc(rand(1,n),c);
r = v(i); % map to v values
  Jeff Miller
      
 on 20 Oct 2018
        3 Comments
  Jeff Miller
      
 on 20 Oct 2018
				Did you download the Cupid files (see the link in my answer)? These define the List class (which handles the cumulative distribution behind the scene). Do the other Cupid demos run correctly?
Well, Cupid may be overkill for your problem, but it does have a lot of flexibility.
  PARTHEEBAN R
 on 22 May 2021
        A random variable X has cdf F(x) = { 0 , if x < − 1 a(1 + x ) , if − 1 < < 1 1 , if x ≥ 1 . Find (1) the value of a, (2) P(X > 1/4 ) and P ( − 0 . 5 ≤ X ≤ 0 ) .
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