How can I use relatively simple code to make bisections in a function until I find the zero?

My coding project asks me to find the zero of a function within a certain domain (-10,10) and I have what I believe is most of the function correct, however I get the error: "Not enough inputs to inline function."

   XL=-10;XR=10;XM=0;

   F = inline('(sqrt(log(x)^2+1))/cosh(x)-(x-(pi/6))+(40/3)*(exp(x))^(-abs(x/5))','XL','XR','num1');

   count=1;

   j=linspace(-10,10,1000);

   while abs(F(XM))>10^(-num1)

      if F(XL)*F(XM)<0

      XM=XR;

      else

      XM=XL;

      end

   end

   count=count+1;

Answer 1

[Kevin Chng]

Hi David Sahed,

There are two ways

1) Use in built MATLAB function

    F = inline('(sqrt(log(x)^2+1))/cosh(x)-(x-(pi/6))+(40/3)*(exp(x))^(-abs(x/5))');
    fzero(F,5);

But this is not bisection method

2) I have modified your logic in your program

   XL=-10;XR=10;XM=0;
   F = inline('(sqrt(log(x)^2+1))/cosh(x)-(x-(pi/6))+(40/3)*(exp(x))^(-abs(x/5))');
   maxiteration=1000;
   Tol = 0.001;

   for i=1:1:maxiteration
       XM = (XL+XR)/2;
       if F(XM) == 0 
           break;
       elseif (XR-XL)<Tol
           break;
       end

       if F(XL)*F(XM)>0
           XL=XM;
       else
           XR=XM;
       end
   end

   display(XM)

Try to understand the logic of bisection once again.

If my answer is working for you, kindly accept it. Thanks.