Read special text file

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Simon REMY
Simon REMY on 14 Oct 2018
Commented: Star Strider on 15 Oct 2018
Hi, guys. I'm trying to convert a python file in Matllab but I have a really hard time doing it since I don't have skills in Python and I'm not realy at ease with Matlab. The python code looks like that :
def LoadConsumptionData(filename):\n",
" dpm = [0,31,28,31,30,31,30,31,31,30,31,30]\n",
" ConsoData = open(filename, 'r')\n",
" Buf = ConsoData.readlines()\n",
" n_lines = len(Buf)\n",
" dt = 0.25\n",
" n_step = int(24. / dt)\n",
" n_days = int(n_lines/n_step)\n",
" P_elec = np.zeros((n_step,n_days), dtype=float)\n",
" date = np.arange(0,n_days)\n",
" time = np.arange(0,24,dt)\n",
" j = 0 # index for the time\n",
" k = 0 # index for the day\n",
" for i in range(n_lines-1):\n",
" (Buf1, Buf2, Buf3) = Buf[i+1].split(',')\n",
" (tmp1, tmp2) = Buf1.split(' ')\n",
" (yy, mm, dd) = tmp1.split('-')\n",
" (h, m, s) = tmp2.split(':')\n",
" t_float = float(h)+float(m)/60.+float(s)/3600.\n",
" j, = np.where(time==t_float)\n",
" k = int(dd)-1+np.sum(dpm[0:int(mm)])\n",
" P_elec[j,k] = float(Buf2)\n",
" return time, date, P_elec\n",
And the txt file looks like that (complete in attachment) :
Date,Total kW, Total kW Moy 15mn
2016-01-01 00:00:00,168,
2016-01-01 00:00:00,160,
2016-01-01 00:15:00,162,
2016-01-01 00:30:00,179,
2016-01-01 00:45:00,181,
2016-01-01 01:00:00,171,
2016-01-01 01:15:00,176,
2016-01-01 01:30:00,191,
2016-01-01 01:45:00,164,
2016-01-01 02:00:00,163,
2016-01-01 02:15:00,173,
2016-01-01 02:30:00,171,
2016-01-01 02:45:00,173,
2016-01-01 03:00:00,173,
2016-01-01 03:15:00,177,
2016-01-01 03:30:00,203,
2016-01-01 03:45:00,170,
2016-01-01 04:00:00,174,
2016-01-01 04:15:00,165,
2016-01-01 04:30:00,182,
........
The first line is not useful. So I have to return 3 vectors, date, time, P_elec but I really have troubles writting the code for it. Does someone can help me with this please ?

Accepted Answer

Star Strider
Star Strider on 14 Oct 2018
This will read your file:
fidi = fopen('Simon REMY B52-2016.txt');
D = textscan(fidi, '%{yyyy-MM-dd HH:mm:ss}D %f', 'HeaderLines',1, 'CollectOutput',1, 'Delimiter',',');
fclose(fidi);
datev = datetime(D{1}, 'Format','yyyy-MM-dd'); % Date Vector
timev = datetime(D{1}, 'Format','HH:mm:ss'); % Time Vector
P_elec = [D{2}]; % Power Vector
The ‘datev’ and ‘timev’ vectors are datetime (link) arrays. See the documentation to understand how to work with them. The ‘P_elec’ vector is a double array,m so you can work with it as is.
  2 Comments
Simon REMY
Simon REMY on 15 Oct 2018
Edited: Simon REMY on 15 Oct 2018
Thanks a lot for your help :) Your solution is simplier than what I was doing :p
Star Strider
Star Strider on 15 Oct 2018
As always, my pleasure!

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