How to flip only some rows inside a matrix?

hey all, if i have vector

A=[2 5 6 7 8 9]

i need it to become a matrix

A=[2 9;
   5 8;
   7 6]

any suggestions?

[the cyclist]

I don't understand the general rule for going from the vector to the matrix. Can you describe it?

Answer 1

[madhan ravi]

A=[2 5 6 7 8 9]

a=fliplr(reshape(A,[3 2]))

a([3 1])= a([1 3])

a=fliplr([a(1:2,:);flip(a(3,:))])

[Abdul Rehman]

that good one Madhan Sir.

[madhan ravi]

Thank you @Abdul

Answer 2

[Abdul Rehman]

i have got Answer for you but its not generic for all matrix.you should look for the end and first element of matrix.

Hopefully it's work for you...

if true
 A=[2 5 6 7 8 9];
 b=(size(A));
 [r c]=size(A);
 j=1;
 gg=c;
 for u=c:-1:c-1 %two iteration for size of vector.
 if(j==1)
  b(j)=A(j); % first value at start 
 end
 if(gg==c)
   b(gg)=A(gg/2); %Size of vector divided by 2 center value at end 
 end
  j=j+1;
  b(j)=A(u);
  b(j+1)=A(j);
  j=j+1;
  end
  b=reshape(b,[2 3])

end

Here Answer:

Answer 3

[Muniba Shah]

A = [2 5 6 7 8 9]; B = reshape(A,[3,2]); C=flipud(B(:,2)); B(:,2)=C; D=fliplr(B(3,:)); B(3,:)=D