Find min values in sequence time series

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dau
dau on 30 Oct 2018
Commented: dau on 31 Oct 2018
Dear all I like to ask your help for this Matlab function to find mean value of a sequence dataset as demonstrated in Figure below.
Column 5 is min of a range values in column 3 based on column 4 (with fd =1).
Thank you very much

Accepted Answer

KSSV
KSSV on 31 Oct 2018
As the data is not given, I have created some random data...check the code:
v = [1 2 3 0 0 0 0 0 2 3 4 0 0 0 0 0 4 5 6 7 0 0 0 0 1 1 1]';
A = rand(27,4) ;
A(:,4) = v ;
w = [false; v~=0 ;false];
starts = find(w(2:end) & ~w(1:end-1)); %Get starts of runs of non-zeros
ends = find(~w(2:end) & w(1:end-1))-1; % Get ends of runs of non-zeros
result = arrayfun(@(s,e) A(s:e,1:3), starts, ends, 'uniformout', false); % extract the respective parts
iwant = cellfun(@mean,result,'uniformout',false)
  2 Comments
dau
dau on 31 Oct 2018
Edited: dau on 31 Oct 2018
Thank you very much for your code. It worked for me now. Again. thank you so much for your kind helps
dau
dau on 31 Oct 2018
Can i ask one more thing, since i want to get min value then i change your expression to:
iwant = cellfun(@min,result,'uniformout',false)
I next step want to divide the iwant to the first column with the same value such as: In the first sequence, the min value equaled -187.1, then next result1 = -187.1 / 421.9 (in the first column). This will repeat to the next sequences, ex: result2 = -596.3 /824.5
Thank you

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