Sum of rows in Magic square using nested for-loops

Hello there,

In my task, we're supposed to create a Magic matrix of 10 and find out the sum of each individual rows before creating a 10x1 vector output displaying the results of each rows. I understand that this can be done simply by using

for i = 1:1:numel(10);

sumRow = sum(matrix, 2);

end

but we are required to do it with nested for-loops instead. Can somebody kindly help me with this? Thank you!

[Guillaume]

Actually, the whole lot can be done without a single loop and would be the efficient way to do it in matlab.

If you are asked to use double for loop, I would thing you have to convert that sum into a loop.

A pointless exercise, in my opinion. There are plenty of ways to teach loops in matlab that don't involve teaching bad habits as well.

Note that as written your loop is pointless. numel(10) is 1.

[Stephen23]

"I understand that this can be done simply..."

without a loop:

sum(matrix,2)

Answer 1

[madhan ravi]

without loop is better:

matrix=magic(10);
sumRow=sum(matrix,2)

with loop (inefficient) according to your requirement:

matrix=magic(10);
n=size(matrix,1);
sumRow = cell(1,n)
for i = 1:n
    sumRow{i} = sum(matrix(i,:), 2);
end
sumRow = cell2mat(sumRow{:})

[Stephen23]

"...we are required to do it with nested for-loops..."

[Bruno Luong]

and furthermore "we" means OP, not one of us

[Kiden Sizhao Wang]

Yes, we do get very unnecessary and inefficient questions at times, unfortunately - but I reckon the intention is to get us to understand the concept and hence apply it better.

Thanks all for the help nonetheless =)