Finding and Storing element row-wise when the matrix has SYM.

Hello everyone, I have a doubt. Suppose i have a matrix whose size is N X M. Lets consider a 6X3 matrix.

A=[1 0 0; 7 0 0;4 5 0;3 5 0;1 4 7; 8 2 1];

What i want to perform is to obtain a new ROW-MATRIX which contain only non-zero element.So the answer would be

     1
     7
     4
     5
     3
     5
     1
     4
     7
     8
     2
     1
     

Can someone help be with this. My matrix is very large and it containg syms instead of numbers,

Answer 1

[madhan ravi]

A=[1 0 0; 7 0 0;4 5 0;3 5 0;1 4 7; 8 2 1];
nonzeros(double(reshape(A',[],1)))
         ^^^^^^----converts to a double from sym or just use vpa (does the same work as double)    

Gives:

ans =

     1
     7
     4
     5
     3
     5
     1
     4
     7
     8
     2
     1

[P K]

Thanks @madhan.

I had to just do this.TRANSPOSE

ans=nonzeros(A')

But, i was getting error with your code when i used it in my case.

Error using symengine

Unable to convert expression into double array.

Anyway thanks.

[madhan ravi]

Anytime :) , glad you worked it out

Note: Don't name a variable ans (use some other names instead).