matching from multiple arrays

I have an array,

ref = [1 1 0 0 1],

and 3 more arrays

a{1}=[1 0 0 0 1] 
a{2}=[1 0 0 0 0]
a{3}=[0 0 1 0 1]

I want to produce an array by comparing ref to all others, such that: if an element in position i in ref matches the element in position i in any of the a{} then it is considered a match otherwise not. In case of a match (ref=1, a=1,0,0), we keep the value of ref (ans=1), otherwise (ref=1, a=0,0,0) the value is flipped (ans=0).

So based on this condition, the output for this example will be

ans=[1 0 0 0 1]

It can easily be done using for loops,

for i=1:5
    match=0;
    for j=1:3
        if(ref(i) == a{j}(i))
            ans(i)=ref(i);
            match=1;
            continue;
        end
    end
    if(~match)
        ans(i)=1-ref(i);
        match=1;
    end
end

but is there a more efficient way to do this?

Answer 1

[madhan ravi]

A=vertcat(a{:});
Result= 1*(any(A) & ref)

[Stephen23]

+1 Neat idea. Could also be on one line:

>> +(any(vertcat(a{:}))&ref)
ans =
   1   0   0   0   1

[madhan ravi]

Thank you Stephen!

Answer 2

[Birdman]

One way:

Result=double(ref & (ref==a{1} | ref==a{2} | ref==a{3}))