How do I design the structure and get the element according to its corresponding index?

I want to get the value of N and M after giving two index variable k and g, as shown in the figure. (k is a number and g is a string)

For example:

k=get_k();
g=get_g();

if k == 1
    N=92;
    if g == 'cc'
        M=300;
    end
end

I tried to use cell to struct a "table",

where the first column is possible values of k,

the second column is the corresponding values of N,

and the third column is a cell contains information about g and its corresponding values of M:

Struct = {1,92,{'a',999;'cc',555;'de',44};...
          2,61,{'a',666;'cc',33;'de',777};...
          3,54,{'a',105;'cc',300;'de',46};...
          6,106,{'a',55;'cc',666;'de',33};...
          10,23,{'a',88;'cc',44;'de',111}}

I want to get the values of N and M using g and k.

My idea is to find the position of the k (i.e., row index of the first column in Struct) and then we can get the value of N.

Also, for the third column (i.e., the corresponding cell) in the same row, if we can find the position of g in that cell, we can get the value of M.

But I don't know how to get these two position.

Answer 1

[Munish Raj]

I understand that you want to access the values of N, M using k, g as your indices.

You can exploit MATLAB’s logical indexing for this application.

The Structure definition is right on track for this purpose.

Assuming you have defined the structure in your question accurately, first column is k, second column is N, followed by a cell array with g, M.

The following code might be helpful

%Define your structure  
Struct = {1,92,{'a',999;'cc',555;'de',44};... 
2,61,{'a',666;'cc',33;'de',777};... 
3,54,{'a',105;'cc',300;'de',46};... 
6,106,{'a',55;'cc',666;'de',33};... 
10,23,{'a',88;'cc',44;'de',111}} 
%Structure is defined 
 
%define the variables g and k 
 
g=6; 
k='a'; 
cellArray=Struct{cell2mat(Struct(:,1))==k,3};  %spotting the corresponding cell array 
logicalCellArray=strcmp(cellArray,'de'); %converting the cellArray to a Logical table 
M=y{logicalCellArray,2}; %obtaining the value of M 
N=Struct{cell2mat(Struct(:,1))==k,2} %Obtaining the value of N  

This can be consized to 2 lines of code, but this code if for your understanding of the algorithm.

Munish Raj

[Linjun He]

Thank you!