Help with plotting sin(X) for a taylor series

okay thanks

Answer 1

[KALYAN ACHARJYA]

Please check

for i = 0:9
        sin_value = sin_value + (-1).^i * input_value^(2.*i+1)/factorial(2.*i+1); 
    end
    end

Is it ok? or It may be

    sin_value(i)=..
    

after iterations finish

    plot(x_values, sin_value) %ensure both having same lengths

[William Paik]

This is what i got when i changed sin_value= to sin_value(i)

Array indices must be positive integers or logical values.

Error in Problem4_Project1_2019_Fixed>calculate_sin (line 35)

sin_value(i) = sin_value + (-1).^i * x_values^(2.*i+1)/factorial(2.*i+1);

Error in Problem4_Project1_2019_Fixed (line 21)

y_values(j) = calculate_sin(x_values(j));

[KALYAN ACHARJYA]

In for loop start i from 1 to 10

[William Paik]

but it needs to start at 0 because thats the def of taylor series

[KALYAN ACHARJYA]

Check with

sin_value(i+1)=..same

Before plot, please ensure both (x and sin) have same lengths

[William Paik]

how do I do that?

[KALYAN ACHARJYA]

I am not asking for do that, just check before plot. Plot x,y, here both must have same lengths