Strange behavior of diff function with symbolic variables
1 view (last 30 days)
Show older comments
Hello everyone,
There is a strange behavior that I encountered while using diff function with symbolic variables, not functions.
Consider the following symbolic expression:
syms theta1
D=0.31*cos(theta1)^2
diff(D,theta1)
>>
-0.62*cos(theta1)*sin(theta1)
This works as expected but when the expression becomes complicated like
syms theta1 theta2 theta3
D=0.31*cos(theta1)^2 - 2.7e-4*sin(theta2) - 0.88*sin(theta2)*(7.3e-5*cos(theta2) - 0.011*sin(theta2) + 3.1e-4) - 0.88*cos(theta2)*(7.3e-5*sin(theta2) - 4.2e-3*cos(theta2) + 4.6e-4) - 1.0*(0.48*sin(theta3) - 0.88*cos(theta2)*cos(theta3))*(5.1e-4*cos(theta3) - 1.7e-4*sin(theta2) - 0.047*sin(theta3) + 0.088*cos(theta2)*cos(theta3) + 9.5e-4*cos(theta2)*sin(theta3)) - 4.1e-4*cos(theta2) + 0.88*sin(theta2)*(3.2e-4*cos(theta3) + 0.073*sin(theta2) + 9.0e-5*sin(theta3) - 1.7e-4*cos(theta2)*cos(theta3) + 5.9e-4*cos(theta2)*sin(theta3)) + 0.31*sin(theta1)^2 + 1.0*(0.48*cos(theta3) + 0.88*cos(theta2)*sin(theta3))*(0.035*cos(theta3) + 5.9e-4*sin(theta2) - 5.1e-4*sin(theta3) + 9.5e-4*cos(theta2)*cos(theta3) + 0.064*cos(theta2)*sin(theta3)) + 0.33;
diff(D,theta1)
>>
0
I receive zero. What is the cause for this? Appreciate your help.
0 Comments
Accepted Answer
Yasasvi Harish Kumar
on 20 Feb 2019
Hi,
Your expression, D contains only 2 theta1 terms(in bold) whose derivatives cancel each other. Differentiation of theta2 and theta3 wrt theta1 is zero. Therefore your answer is zero.
D =0.31*cos(theta1)^2 - 2.7e-4*sin(theta2) - 0.88*sin(theta2)*(7.3e-5*cos(theta2) - 0.011*sin(theta2) + 3.1e-4) - 0.88*cos(theta2)*(7.3e-5*sin(theta2) - 4.2e-3*cos(theta2) + 4.6e-4) - 1.0*(0.48*sin(theta3) - 0.88*cos(theta2)*cos(theta3))*(5.1e-4*cos(theta3) - 1.7e-4*sin(theta2) - 0.047*sin(theta3) + 0.088*cos(theta2)*cos(theta3) + 9.5e-4*cos(theta2)*sin(theta3)) - 4.1e-4*cos(theta2) + 0.88*sin(theta2)*(3.2e-4*cos(theta3) + 0.073*sin(theta2) + 9.0e-5*sin(theta3) - 1.7e-4*cos(theta2)*cos(theta3) + 5.9e-4*cos(theta2)*sin(theta3)) + 0.31*sin(theta1)^2 + 1.0*(0.48*cos(theta3) + 0.88*cos(theta2)*sin(theta3))*(0.035*cos(theta3) + 5.9e-4*sin(theta2) - 5.1e-4*sin(theta3) + 9.5e-4*cos(theta2)*cos(theta3) + 0.064*cos(theta2)*sin(theta3)) + 0.33;
I hope I could help.
Regards
More Answers (0)
See Also
Categories
Find more on Assumptions in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!