How do I tell Matlab a loop index is an integer?

I am perplexed by the fact that niether loop indeces or the number 3 are considered integers.

The script (called WhyNotIntegers)

for i = 1:3
    idivide(i,3,'round')
end

produces these errors when run:

Error using idivide>idivide_check (line 66)

At least one argument must belong to an integer class.

Error in idivide (line 42)

idivide_check(a,b);

Error in WhyNotIntegers (line 2)

idivide(i,3,'round')

Error in run (line 96)

evalin('caller', [script ';']);

Answer 1

[Image Analyst]

They're doubles that just happen to have integer values. Convert them to integers since that's what idivide wants. Try this:

for k = 1:3
    idivide(int32(k), int32(3),'round')
end

[Alexander MacFarlane IV]

Thanks to both of you for the fast answers.

Stephan got there first, but this told me exactly what I needed to do.

Alex

Answer 2

[Stephan]

Hi,

by default numbers in Matlab are double. cast them to integer:

int32(i)

Read here:

https://de.mathworks.com/help/releases/R2016b/matlab/matlab_prog/integers.html#f2-54113

Best regards

Stephan