How can i loop a matrix without knowing is size?

Hello!
So, i'm trying to make a loop where i have a matrix to go through and save their elements in a vector. Just note that i don't know the size of the matrix. So how can i do it?
Thanks!

2 Comments

Are you somehow prevented from using the size function?
No, i just didn't know how to use :D

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 Accepted Answer

So, you have two matrices, one outside the loop, and one inside? Which one are you not sure about the size of?
If it is the outside loop you can set the loop bounds to be dependent on the size of the matrix.
for i = 1:size(mat,1) % (mat,1) for rows, (mat,2) for columns and so on

6 Comments

Yes, that's it!
So it will be something like this... ?
mat = [ 1 2 3 ; 4 5 6]
v = zeros(1,6)
for i = 1: size(mat,1)
v(i) = mat(i)
end
P.S: i want this: v = [1 2 3 4 5 6]
(In this case i know the size of the matrix but it's just an example)
Not quite. Using size in this manner will only loop through one dimension. Because you have two dimensions in 'mat' then you would actually need to do two loops, one for each direction.
However, because you are just trying to reorganize your data into a single dimension you can actually just use the reshape function.
v = reshape(mat,[n,1]);
This is just an example. I pretend to use this code in a more complex function, but i need some bases...
I made this, but i still don't get the result. Where am i wrong?
mat = [ 1 2 3 ; 4 5 6]
v = zeros(1,6)
for i = 1: size(mat,1)
for j = 1:size(mat,1)
v(i) = mat(i,j)
end
end
It's your indexing for v. Your i loop only goes from 1:2, so indexing v with (i) will just give you v(1) or v(2). You need to change this to be a combination of i and j.
v((i-1)*size(mat,2)+j) = mat(i,j);
Also, you need to change your dimension your specifying for the innner loop. When you call size() the first input is the matrix, and the second input is the dimension. 1 is rows, 2 is columns, 3 is sheets, etc.
Thank you so much! You helped me a lot :)
Have a nice day xx

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