Write this without a for loop?

for c= delaySamples+1:length(audioVec)
EchoVec(c)=audioVec(c)+z(c-(delaySamples)*EchoGain);
end

4 Comments

Andrei Bobrov
Andrei Bobrov on 3 Mar 2019
Edited: Andrei Bobrov on 3 Mar 2019
What is z, EchoGain?
heres the entire code for my function
function EchoVec=soundEcho(audioVec,Fs,delay,EchoGain)
EchoGain=input('enter how loud echo should be:');
delay=input('enter in a delay value in seconds:');
delaySamples=Fs*delay;
z=[zeros(1,delaySamples),audioVec'];
audioVec(length(delaySamples))=0;
for c= delaySamples+1:length(audioVec)
EchoVec(c)=audioVec(c)+z(c-(delaySamples)*EchoGain);
end
sound(EchoVec,Fs);
end
madhan ravi
madhan ravi on 3 Mar 2019
Edited: madhan ravi on 3 Mar 2019
when a third person runs your code (it is not possible to run) , nobody has the power to know what is in your computer
Michelle, if you feel that the question is unclear, then as you are the person who posted the question, you should be the one who clarifies it to make it more clear.

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Answers (1)

If audioVec is a column array and you ensure that (delaySamples)*EchoGain is a valid index:
c = delaySamples+1:length(audioVec);
EchoVec(delaySamples+1:length(audioVec))=audioVec(delaySamples+1:end)+z(c-(delaySamples)*EchoGain);

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on 3 Mar 2019

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