erasing specifi rows from a cell matrix

Dear all,
I have
A={
'12/08' ' '
'01/09' ' '
'02/09' ' '
'03/09' ' '
'03/09' ' '
'04/09' ' '
'05/09' ' '
'06/09' ' '
'07/09' ' '
'08/09' ' '
'09/09' ' '
'10/09' ' '
'11/09' ' '
'12/09' ' '
'01/10' '33 '
'01/10' '55 '
'02/10' ' '
'03/10' ' '
'04/10' ' '
'05/10' ' '
'06/10' ' '
'07/10' ' '
'08/10' ' '
'09/10' ' '
'10/10' ' '
'11/10' ' '
'12/10' ' '
'01/11' '123 '
'01/11' ' 321'
'02/11' ' '
'03/11' ' '
'04/11' ' '
'05/11' ' '
'06/11' ' '
'07/11' ' '
'08/11' ' '
'09/11' ' '
'10/11' ' '
'11/11' ' '}
I want to erase the second duplicate so as to have
A={
'12/08' ' '
'01/09' ' '
'02/09' ' '
'03/09' ' '
'03/09' ' '
'04/09' ' '
'05/09' ' '
'06/09' ' '
'07/09' ' '
'08/09' ' '
'09/09' ' '
'10/09' ' '
'11/09' ' '
'12/09' ' '
'01/10' '33 '
'02/10' ' '
'03/10' ' '
'04/10' ' '
'05/10' ' '
'06/10' ' '
'07/10' ' '
'08/10' ' '
'09/10' ' '
'10/10' ' '
'11/10' ' '
'12/10' ' '
'01/11' '123 '
'02/11' ' '
'03/11' ' '
'04/11' ' '
'05/11' ' '
'06/11' ' '
'07/11' ' '
'08/11' ' '
'09/11' ' '
'10/11' ' '
'11/11' ' '}
thanks

1 Comment

what about
'03/09' ' '
'03/09' ' '
they are identical, will you remove one ?

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 Accepted Answer

[x,y]=unique(A(:,1),'stable');A=A(y,:)

More Answers (1)

[~,b] = unique(A(:,1),'first')
Aout=A(sort(b),:)
or
[c,c,c] = unique(A(:,1));
Aout=A(~([false;diff(c)==0]&~cellfun(@isempty,regexp(A(:,2),'\d*'))),:);

3 Comments

Hi andrei,
the code above erases the first and not the second duplicate
thanks
no, erases the second duplicate
no, does'nt erase the second, it erase the second after sorting, for example change a value 321 with 32.

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