Generate random number from a two-parameter exponential distribution
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Alexis Stevenson
on 21 Mar 2019
Edited: Alexis Stevenson
on 21 Mar 2019
Hello everybody,
I am looking for a way to easily generate random numbers from a two-parameter exponential distribution. The probability density function is:
. I am aware of expand() but it does not seem to include the two-parameter distribution.
. I am aware of expand() but it does not seem to include the two-parameter distribution.Do you have any idea how I could achieve that?
Thank you very much.
Alexis
4 Comments
Torsten
on 21 Mar 2019
What is the support of f ?
I ask because if support(f) = IR+, f is only a probability density function if gamma = 0.
Accepted Answer
Torsten
on 21 Mar 2019
gam = ...;
lambda = ...;
n = 100;
x = gam - log(1-rand(n,1))/lambda
give you 100 random numbers distributed according to your two-parameter distribution.
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