rank keywords using length
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Dear sir,
I rank the keywords firstly according to its occurance.Next the output keywords should be ranked according to its length.how it is possible ?Please help me sir.the code i used is attached below.
fid = fopen('file.txt');
s=textscan(fid,'%s')
fclose(fid);
str=s{:}
[ii,jj,kk]=unique(str)
freq=hist(kk,(1:numel(jj))')'
[ii num2cell(freq)]
output:
'Audrey' [1]
'British' [1]
'Brussels' [1]
'Hepburn' [1]
'Ixelles,' [1]
'actress' [1]
'dancer' [1]
'fashion' [1]
'female' [1]
'film' [1]
'humanitarian' [1]
'icon' [1]
'legend' [1]
'model' [1]
'screen' [1]
'third-greatest' [1]
0 Comments
Accepted Answer
dpb
on 30 Mar 2019
[~,il]=sort(l,'descend');
K>> s(il)
ans =
16×1 cell array
{'third-greatest'}
{'humanitarian' }
{'Brussels' }
{'Ixelles,' }
{'British' }
{'Hepburn' }
{'actress' }
{'fashion' }
{'Audrey' }
{'dancer' }
{'female' }
{'legend' }
{'screen' }
{'model' }
{'film' }
{'icon' }
K>>
2 Comments
dpb
on 31 Mar 2019
"l" is the name of the variable holding the list -- I used "l" for the illustration, you need to use whatever it is you have-- "s" above.
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