Why does matlab create a single row when creating a matrix of multiple columns?

I have to following problem: In reality i have two columns consisting of 250k rows, but i fail to creat a matrix by just using matrix = [column1 column2]. Did i change something in my settings? See the following simple example of my problem

a = [1:10]'

b = [1:10]'

c = [a b]

The answer is

"Columns 1 through 18

1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8

Columns 19 through 20

9 10 "

instead of a matrix consisting of two columns. What is going on here?

[Star Strider]

The code you posted works correctly for me, and produces ‘c’ as a (10x2) matrix.

[mootje_3000]

This question/thread needs to be deleted. I'm did something wrong in my code after creating the matrix.

[Star Strider]

I can’t find a normdata function in the online documentation. (It’s for R2019a, however it should cover all recent releases.)

See if running this line from a script or your Command Window reveals anything:

which normdata -all

That’s the only thing I can think of that might resolve the issue.

[madhan ravi]

Original question:

In case if the OP edits the content of the question.

I have to following problem: In reality i have two columns consisting of 250k rows, but i fail to creat a matrix by just using matrix = [column1 column2]. Did i change something in my settings? See the following simple example of my problem

a = [1:10]'

b = [1:10]'

c = [a b]

The answer is

"Columns 1 through 18

1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8

Columns 19 through 20

9 10 "

instead of a matrix consisting of two columns. What is going on here?

[mootje_3000]

I did the following wrong: A matrix consisting of 250k rows and 4 columns, when I wanted to delete a number of rows I used normdata(deleterows) = [], while I should've used normdata(deleterows,:)=[].

Thank you so much for replying madhan ravi and star strider. Sorry for any inconvenience.

[madhan ravi]

No need for an apology, mistakes are inevitable sometimes.

Answer 1

[madhan ravi]

[a,b] - you were concatenating two row vectors horizontally which results in a row vector, instead do:

c = [a(:) b(:)] 
%or
c = [a;b].'

Also this works:

>> a = [1:10]'
   b = [1:10]'
   c = [a b]

a =

     1
     2
     3
     4
     5
     6
     7
     8
     9
    10

b =

     1
     2
     3
     4
     5
     6
     7
     8
     9
    10

c =

     1     1
     2     2
     3     3
     4     4
     5     5
     6     6
     7     7
     8     8
     9     9
    10    10

>>