How to recognize if there is in a character a point '.'?
4 views (last 30 days)
Show older comments
Dear Matlab community,
Maybe somebody can help me with the following problem. For a project I would if there is a character a point '.' by scanning each element of the character by returning a true (1), false (0) as answer in an array. I tried the following:
xx='00-055.0'
isstrprop(xx,'punct')
ans =
1×8 logical array
0 0 1 0 0 0 1 0
At the moment it also shows e.g. '-', but is there a method to find explicitely the point '.'?
Thank you.
Regards
0 Comments
Accepted Answer
madhan ravi
on 8 Apr 2019
Edited: madhan ravi
on 8 Apr 2019
contains(regexp(xx,'.','match'),'.')
%or
strcmp(regexp(xx,'.','match'),'.')
%or
cellfun(@(x)x=='.',regexp(xx,'.','match'))
Gives:
ans =
1×8 logical array
0 0 0 0 0 0 1 0
4 Comments
Guillaume
on 8 Apr 2019
Well, then you don't need to use a regular expression engine to split a char vector into a cell array of individual characters
num2cell(xx)
will do the job faster.
More Answers (2)
Guillaume
on 8 Apr 2019
Edited: Guillaume
on 8 Apr 2019
Edit: I misunderstood the question. It's even simpler than what I initially wrote.
Simply:
xx == '.'
If you want to check multiple characters at once, e.g. . and +
ismember(xx, '.+')
--------
Original answer
Simply
contains(xx, '.')
or
any(xx == '.') %probably faster than contains but only work as long as you're searching just for one character
if wanting to check if any of several characters are in xx, e.g. . and +:
any(ismember(xx, '.+')) %are any character of xx member of the set .+ ?
5 Comments
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!