Skipping even indices in a for-loop and subsequently avoiding the odd values to appear in the output

10 views (last 30 days)
Through a nested-for-loop for n=1 and m=1,3 i want to acquire a matrix A with elements a1 and a2
m_length = 3;
n_length = 1;
for n=1:1:n_length
for m=1:2:m_length
a1(n,m) = ((n-1)+m);
a2(n,m) = ((n-1)+m);
end
end
A = [a1 a2];
The above would output A as
A = [1,0,3,1,0,3]
It takes into account the even values of m too (and equates them to 0).
But what i require is purely the odd values of m (i.e. m=1,3) in the matrix.
What i would like to see is:
A = [1,3,1,3]
PS: In the original problem, n = 0,1,2,3,4...n_length and m = 1,3,5,7,9...m_length.
I shortened m and n and their total lengths for ease of explaining the problem.

Accepted Answer

Dennis
Dennis on 15 Apr 2019
When you assign a value to A(3,3)=1, Matlab will create a Matrix of the size 3,3 and will fill empty fields with 0.
A(3,3)=1
A =
0 0 0
0 0 0
0 0 1
This is what is happening in your code. One possible solution might be to fix the index of your matrix:
m_length = 3;
n_length = 1;
for n=1:1:n_length
for m=1:2:m_length
a1(n,(m+1)/2) = ((n-1)+m);
a2(n,(m+1)/2) = ((n-1)+m);
end
end
A = [a1 a2];

More Answers (0)

Categories

Find more on Environment and Clutter in Help Center and File Exchange

Products


Release

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!