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How to obtain the minimum values of an array?

Asked by Oscar Espinosa on 8 Jun 2019
Latest activity Commented on by Oscar Espinosa on 10 Jun 2019
I'm trying to get the minimum values of three vectors. Assuming that the length of the vectors is 1x4, I need to get 4 minimums. Also one of the vectors has as values a constant. I'm attaching the code. The important part is on lines 12 to 15.
function [x_t,Re,eta_c,C_f] = CXAPWING(b,b_slats,x_thickness,x_camber,M)
%%% Коэффициент профильного сопротивления крыла
h_polish = 1e-6; %micro
V = M*299.45;
Re = V*b/3.5232e-5;
F1 = 1.3+0.6*M*(1-0.25*M^2);
hbRe = h_polish*V/3.5232e-5;
F2 = log10(abs(hbRe-1));
F3 = (2.2-0.08*M^2)/(1+0.312*M);
n = 5+F1*(1-(F2/F3)^2)^0.5;
x_t_1 = 10^n/Re;
x_t_2 = sqrt(x_thickness*x_camber);
x_t_3 = b_slats/b;
x_t = min([x_t_1 x_t_2 x_t_3]);
if Re < 4.85e5
C_f = 1.328/sqrt(Re);
elseif Re > 3e7
C_f = 0.455/(log10(Re))^2.58;
else
C_f = (0.455./log10(Re).^2.58).*((1-x_t+(40*x_t^0.625)/Re.^0.375).^0.8)';
end
% nc_xt = [1.4072 1.3722 1.3536 1.3103 1.2557; 0 0.1 0.2 0.3 0.4]; % 0.11
nc_xt = [1.3323 1.3063 1.2917 1.2552 1.2115; 0 0.1 0.2 0.3 0.4]; %0.09
if x_t > 0 && x_t < 0.1
eta_c = INTERPOLATION(nc_xt(2,1),nc_xt(1,1),nc_xt(2,2),nc_xt(1,2),x_t);
elseif x_t > 0.1 && x_t < 0.2
eta_c = INTERPOLATION(nc_xt(2,2),nc_xt(1,2),nc_xt(2,3),nc_xt(1,3),x_t);
elseif x_t > 0.2 && x_t < 0.3
eta_c = INTERPOLATION(nc_xt(2,3),nc_xt(1,3),nc_xt(2,4),nc_xt(1,4),x_t);
else x_t > 0.3 && x_t < 0.4
eta_c = INTERPOLATION(nc_xt(2,4),nc_xt(1,4),nc_xt(2,5),nc_xt(1,5),x_t);
end
end

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1 Answer

Answer by madhan ravi
on 8 Jun 2019
 Accepted Answer

Have a look at mink() else use sort() and pick the first four values if you’re using older version.

  1 Comment

sort() did helped me!

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