Regarding the plot and for loop

Hey, I have a one small problem.

This is my sample code: Just focus on only matrix O ;

function my_plotinstat

n = 4; % may be 5, 10, 50, 100 doen't matter now

load('Measuring_Data.mat');

% f = 2000

% T1 is a 2-D matrix of size n*n , assume any numbers

[f,T1] = surendra13_Instat(Measuring_Data);

[Lambda, A, B, D,V, Rho,cP,P, M, A1,O, X, M_1] = Matrix_surendra14;

%Umgebungstemperature = zeros(1,length(f)); % Vektor mit konstanter Umgebungstemeprature

%Umgebungstemperature(1,:)=20;

figure

hold ('on');

for plotnumber = 1:n

if plotnumber == X{1,1}

plot(f/60,T1(plotnumber,:),'Color','g','LineWidth',2,'LineStyle','-');

legend(X{1,2});

elseif plotnumber == X{2,1}

plot(f/60,T1(plotnumber,:),'Color','c','LineWidth',2,'LineStyle','--');

legend(X{2,2});

elseif plotnumber == X{3,1}

plot(f/60,T1(plotnumber,:),'Color','b','LineWidth',2,'LineStyle',':');

legend(X{3,2});

elseif plotnumber == X{4,1}

plot(f/60,T1(plotnumber,:),'Color','m','LineWidth',2,'LineStyle','-.');

legend(X{4,2});

elseif plotnumber == X{5,1}

plot(f/60,T1(plotnumber,:),'Color','g','LineWidth',2,'LineStyle','o');

legend(X{5,2});

elseif plotnumber == X{6,1}

plot(f/60,T1(plotnumber,:),'Color','g','LineWidth',2,'LineStyle','d');

legend(X{6,2});

elseif plotnumber == X{7,1}

plot(f/60,T1(plotnumber,:),'Color','y','LineWidth',2,'LineStyle','s');

legend(X{7,2});

elseif plotnumber == X{8,1}

plot(f/60,T1(plotnumber,:),'Color','y','LineWidth',2,'LineStyle','h');

legend(X{8,2});

elseif plotnumber == X{9,1}

plot(f/60,T1(plotnumber,:),'Color','y','LineWidth',2,'LineStyle','p');

legend(X{9,2});

elseif plotnumber == X{10,1}

plot(f/60,T1(plotnumber,:),'Color','y','LineWidth',2,'LineStyle','>');

legend(X{10,2});

elseif plotnumber == X{11,1}

plot(f/60,T1(plotnumber,:),'Color','y','LineWidth',2,'LineStyle','<');

legend(X{11,2});

elseif plotnumber == X{12,1}

plot(f/60,T1(plotnumber,:),'Color','y','LineWidth',2,'LineStyle','v');

legend(X{12,2});

end

end

hold('on')

plot(f/60,Umgebungstemperature,'Color','b','LineWidth',2);

grid on

box off

end

% xlabel('Zeit in min','FontSize',14);

% ylabel('Temperatur in °C','FontSize',14);

% title('instationäre Knotentemperatur','FontSize',16); % hier im Titel den Knoten xx einfügen oder "der Welle", "des Gehäuse, "der Isolierung", "des RWDR", "des Dichtkontakt", "des Öl" oder "der Luft", je nach Ausgabeparameter

% ylim([0,250]);

% hold('off');

Here X is a cell array, it ask the user to enter which one to be plotted for an example:

X = { 1 , 'Node1';

3 , 'Node3';

4 'Node4'};

Here I am allowing user to plot only max 12 nodes at a time or even less also, depending upon the user.

When I run the code it is showing below error;

Index exceeds matrix dimensions.

Error in my_plotinstat (line 24)

elseif plotnumber == X{4,1}.

Here I know Dimension of the cell array X is not 5 *5 or even more according to code. it is 3*3 now.

But my problem is code should run according to the user input, it doesn't matter whether it is 3*3 or 4*4.

I think here I have to use for loop or if statement to make it correct. But I am not getting what to use or how to use after the first for loop.

Could anyone kndly suggest me an answer?

Thanks in advance.

Answer 1

[Bob Thompson]

The problem is occurring because your X sample is not consecutive values, but you want the loop to look for consecutive values.

When plotnumber == 2, then it is not able to make the match with X ( which contains 1 3 4), and so proceeds along to the next elseif condition. There it is looking for plotnumber == X{4,1}, but this returns the error because X{4,1} does not exist.

[surendra kumar Aralapura mariyappa]

@Bob Nbob, Here I am using cell array, which means I am giving the address of the value.

For an example, X = { 2, 'Node2;

5, 'Node5';

6, 'Node6'};

So here What I am doing is

When the for loop comes first it will go from 1 till n.

Likewise 1 2 3 4 5,

So I need node 2 to be plotted so when plotnumber == 2 which means X{1,1} then plot should be plotted. Likewise for other nodes also.

foran example plotnumber == 5 so X{2,1} so plot will be plotted.

As you said X{4,1} doesn't exist that I knew. But what I need is logic to fix it out. May be using for loop or if statement.

I doen't matter whether I am skipping the number or not in cell array. I am just comparing the element of an cell array with the plotnumber by giving the address of it(like pointers).

I think you understood now.

[Bob Thompson]

It is a logic error. For your example, what happens when plotnumber == 1?

In any case, you should be able to remove the entire if statement and fix your problem all at once. What follows is a rough sample of what I had in mind. You may need to make adjustments to it.

p = cell2mat(X(:,1));
for plotnumber = 1:n;
    c = find(p==plotnumber);
    if ~isempty(c)
        % Do you stuff here. Index row of cells with c value
    end
end

[surendra kumar Aralapura mariyappa]

@Bob Nbob, Thank you for the suggestion. I didn't think about the other plotnumbers.

But if I use your idea, I can't add legend in the plot.

Kindly see the code.

function my_plotinstat

n = 20;

load('Measuring_Data.mat');

[f,T1] = surendra13_Instat(Measuring_Data);

[Lambda, A, B, D,V, Rho,cP,P, M, A1,O, X,M_1] = Matrix_surendra14;

Umgebungstemperature = zeros(1,length(f)); % Vektor mit konstanter Umgebungstemeprature

Umgebungstemperature(1,:)=20;

figure

hold ('on');

p = cell2mat(X(:,1));

for plotnumber = 1:n

c = find(p == plotnumber, 1);

if ~isempty(c)

c = plotnumber;

if c >= 1 && c <= ceil(n./4)

plot(f/60,T1(c,:),'Color','m','LineWidth',2,'LineStyle','-');

% legend(X{c,2});

elseif c > ceil(n./4) && c <= ceil(n./2)

plot(f/60,T1(c,:),'Color','c','LineWidth',2,'LineStyle',':');

%legend(X{c,2});

elseif c > ceil(c./2) && c <= ceil(3*n./4)

plot(f/60,T1(c,:),'Color','r','LineWidth',2,'LineStyle','d');

% legend(X{c,2});

elseif c > ceil(3*n./4) && c <=n

plot(f/60,T1(c,:),'Color','y','LineWidth',2,'LineStyle','s');

% legend(X{c,2});

end

end

end

hold('on')

plot(f/60,Umgebungstemperature,'Color','b','LineWidth',2);

grid on

box off

end

Here as I said earlier. X cell array is a user input. So user will give both plotnumber(p) and name to that plot. Like below

Now user wants node 4 and 10 should be plotted.

X = { 4, 'Node4'; 10, 'Node10'};

Now only line will be plotted but legend will not be there. so please check my code you can understand better what I am telling.

I need legend also.

is it also possible to give different color or pattern to the line plot? In my code I am considering only 4 color and 4 pattern. is there any way to make at least ten color or pattern for max 10 user input ?

Thanks in advance.

[Bob Thompson]

I believe you need to just do legend as all of the names.

legend(X(:,2))

If that sets them up out of order than I would suggest copying them into a specific array, and then inducing them all at once after the loop from that array. Either way it should be happening outside of the loop all at once.

As for increasing the possible size of the input array, I would suggest creating a variable which contains the different possible colors and styles of lines, and then calling that in based on indexing.

fmt = {'b', '-';
       'k', '.'};
plot(f/60,T1(c,:),'Color',fmt{c,1},'LineWidth',2,'LineStyle',fmt{c,2});