Sort a cell array of char
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Hi,
I have a cell array of chars (some of the cells should be strings while other should be doubles). Now I am trying to sort several of the rows that should be doubles and I get, of course, a sort from the left of the number as : 1001, 112, 14.. Tried to convert to double with both writing sort(double(...)) and cellfun(@double, ...,'Uniformoutput', false) and it won't accept: 1) ??? Error using ==> double Conversion to double from cell is not possible." 2)??? Error using ==> sort Input argument must be a cell array of strings. What can I do to get 14, 112, 1001... Thank you Keren
Accepted Answer
More Answers (1)
Teja Muppirala
on 4 Apr 2011
Instead of just "double" you should use "str2double". I'm pretty sure that does what you want.
A = {'1001', '112', '14'}
B = str2double(A)
[Bsorted,ordering] = sort(B)
3 Comments
Jan
on 4 Apr 2011
Correct, but the SSCANF(SPRINTF('%g,', C{:}), '%g,') approach is much faster than STR2DOUBLE for a {1 x 5000} cell (Matlab 2009a):
C = cell(1, 5000);
for i=1:5000; C{i}=sprintf('%.0f', rand*1000); end
tic; d = str2double(C); toc % 0.20 sec
tic; e = sscanf(sprintf('%g,', C{:}), '%g,'); toc % 0.01 sec
Teja Muppirala
on 4 Apr 2011
Wow, that's pretty slick! I wouldn't have thought of that.
Jan
on 4 Apr 2011
And SPRINTF still wastes time, because it does not pre-allocate the output. Therefore using http://www.mathworks.com/matlabcentral/fileexchange/26077-cstr2string will make it twice as fast:
tic; e = sscanf(CStr2String(C, ','), '%g,'); toc % 0.005 sec
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