How can I shift the elements in a vector without losing the elements? just shift the order

If I have

A = [1,2,3,4,5,6,7,8,9,10];

I want specific consecutive number of elements (e.g. 6,7,8) to shift left or shift right n bits. Assume I know the number orders and elements in the array A. I also know how many numbers I want to shift.

I need, (e.g. shift left 2 bits)

B = [1,2,3,6,7,8,4,5,9,10];

Or (e.g. shift left 1 bit)

B = [1,2,3,4,6,7,8,5,9,10];

Or (e.g. shift right 2 bits)

B = [1,2,3,4,5,9,10,6,7,8];

Thanks

Nur

Answer 1

[Nurahmed]

I am new to Matlab, but after one day struggle, I finally found the solution to my problem. It was fun!

A=1:10;
startPos=4;
numMove=2;
shiftBit=3;     % minus--moveLeft; positive--moveRight; zero--don'tMove
B = A;
B(startPos+shiftBit:startPos+shiftBit+numMove-1)=A(startPos:startPos+numMove-1);
if shiftBit<=0
oldNum = A(startPos+shiftBit:startPos-1);
B(startPos+shiftBit+numMove:startPos+numMove-1)=oldNum;
else 
oldNum = A(startPos+numMove:startPos+numMove+shiftBit-1);
B(startPos:startPos+shiftBit-1)=oldNum;
end

Answer 2

[dpb]

Sorta' inconsistent definition, but look at

>> A=1:10;
>> circshift(A(4:end-2),-2)          % case 1
ans =
     6     7     8     4     5
>> 
>> circshift(A(6:end),2)             % case 3
ans =
     9    10     6     7     8
>>

Have to just decide what it means to "shift" -- the latter above is actually a circular shift of the elements within the total vector while the first is more like swapping positions of a lesser subset altho can be written with circshift but selecting proper subset of the overall vector and pre- or post-pending the remainders.

With only the examples but not the logic behind "why" the difference, it's your call as to how to decide what is what really want.