# Plotting integral over an interval

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Angelica Mercy Calip on 9 Jul 2019
Answered: infinity on 9 Jul 2019
I want to integrate the following over the interval x0 = 0:2:8 . I have tried using arrayfun:
x0 = 0:2:8;
cai= @(theta) ((4.*pi.*x0.*cos(theta).*sin(theta)+8.*pi.*cos(theta).*cos(theta).*sin(theta))./(1+0.5.*x0+cos(theta)));
xval = arrayfun(@(uplim) integral(cai, 0, uplim, 'ArrayValued',true), x0);
plot(x0, xval)
grid
But I got the following error code:
Error using arrayfun
Non-scalar in Uniform output, at index 1, output 1.
Set 'UniformOutput' to false.
Error in PlottingFx (line 6)
xval = arrayfun(@(uplim) integral(cai, 0, uplim, 'ArrayValued',true), x0);
Can anyone help me?

infinity on 9 Jul 2019
Hello,
The way you try to plot the integral may be not correct, for x0 you can compute the integral by using the integral fuction with repsect to theta. This code below may help you understand this well
x0 = 0:2:8;
cai= @(theta) ((4.*pi.*x0.*cos(theta).*sin(theta)...
+8.*pi.*cos(theta).*cos(theta).*sin(theta))...
./(1+0.5.*x0*cos(theta)));
xval = integral(cai, 0, pi,'ArrayValued',true);
plot(x0, xval)
grid
Also, I fix an mismatch between your code and your provided function
./(1+0.5.*x0+cos(theta)));
I change it to
./(1+0.5.*x0*cos(theta)));
which is correct with your given equation.

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