extract the most repeated element of a cell array

A={[],[18],[14],[],[],[],[14],[],[14],[18]};

I want to get most repeated element in A, (except nan).

result should be

B=14

for this reason I use this code.

B=mode(cell2mat(A));

The problem is that in some of iteration in For loop, A changes to A={[],[],[],[],[]} (A changes in each loop)

So, when I used above code, give me this warning

Warning: MODE of a 0-by-0 matrix is NaN; result was an empty matrix in
previous releases. 
> In mode (line 79) 

I tried to use this code, but program stops it some iteration and I need to click Enter key.

if ~isnan(cell2mat(outlier_test))
    B=mode(cell2mat(A));
 end

It means that if I omit above code, my program runs without any pressing on Enter key.

So, I do not know how to fix it.

Answer 1

[KSSV]

clc; clear all ;
A={[],[18],[14],[],[],[],[14],[],[14],[18]};

B = cell2mat(A) 

[a,b]=hist(B,unique(B)) ;
[b' a']

[KSSV]

    14     3
    18     2

The above says 14 repeated for 3 times; 18 repeated for 2 times. If you want the maximum repeated one:

    b(find(max(a)))

Yes thats fine.

[NA]

I should use this one

result=b((max(a)==a));