Combination of sub-matrices generated within a for loop

3 views (last 30 days)
Rengin on 13 Aug 2019
Commented: Bruno Luong on 13 Aug 2019
clear;
clc;
close all;
n=[3 1 2];
rad=[0.04 0.02 0.01];
h=[10 12 15];
for kk=1:length(n)
matrix=zeros(n(kk),n(kk));
for ii=1:n(kk)
for jj=1:n(kk)
val=rad(kk)*h(kk);
matrix(ii,jj)=val;
end
end
end
% Dear users, if you put a debug at the very last "end" (row 17), you can
% see that I aim to generate 3 sub-matrices having the size of 3x3, 1x1 and
% 2x2 (see n=[3 1 2]). I want to combine each sub-matrix one each other diagonally.
% I want to get the matrix as a result below:
matrix=[0.4 0.4 0.4 0 0 0;0.4 0.4 0.4 0 0 0;0.4 0.4 0.4 0 0 0;0 0 0 0.24 0 0;0 0 0 0 0.15 0.15;0 0 0 0 0.15 0.15];
%Is there any simple way to do it?
%Thanks in advance!
3 CommentsShowHide 2 older comments
Bruno Luong on 13 Aug 2019
"The calculation of Val is different."
You might try to learn deeper how computer programming actually works, if you get stuck everytime the values change then you miss the whole purpose of programming.

Sign in to comment.

Accepted Answer

infinity on 13 Aug 2019
Hello,
There are various solutions for this question, one of the closet one to your current code could be
clear;
clc;
close all;
n=[3 1 2];
rad=[0.04 0.02 0.01];
h=[10 12 15];
matrix = zeros(sum(n));
for kk=1:length(n)
% matrix=zeros(n(kk),n(kk));
for ii=1:n(kk)
for jj=1:n(kk)
val=rad(kk)*h(kk);
matrix(ii+sum(n(1:kk-1)),jj+sum(n(1:kk-1)))=val;
end
end
end
0 CommentsShowHide -1 older comments

Sign in to comment.

Categories

Find more on Operating on Diagonal Matrices in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!