How do I check if a folder exists which has a variable name?
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Hi,
I want to check if the created folder already exists. But the name of the folder depends on the file I work with.
fname = Measurement_20190829_18_15_10.bin
if ~exist('Figures' fname(11:end-4), 'dir')
mkdir('Figures', fname(11:end-4));
end
I have no clue how to make this work.
I always get Invalid expression with a marker on fname.
Please help.
Thank you!
3 Comments
Stephen23
on 29 Aug 2019
Edited: Stephen23
on 29 Aug 2019
"How does fileparts help me in this example?"'
Instead of using this fragile, very non-robust code to obtain the filename without the extension:
fname(11:end-4)
you can simply use robust fileparts:
[~,name] = fileparts(fname);
"But the exist does not work properly."
exist does work properly. Read the last four lines of my previous comment.
Accepted Answer
Stephen23
on 29 Aug 2019
Edited: Stephen23
on 29 Aug 2019
[~,name] = fileparts(fname);
exist(fullfile('Figures',name), 'dir')~=7
Note that exist does NOT return a boolean value, it returns different integers for specific object types. It is strongly recommended to test for the specific integer that is returned for the specific object type that you are trying to locate.
More Answers (1)
Johannes Fischer
on 29 Aug 2019
Edited: Johannes Fischer
on 29 Aug 2019
Your code is trying to store in fname the content of the field 'bin' of the struct 'Measurement_20190829_18_15_10', which propably doesnt exist.
fname needs to be a char array:
fname = 'Measurement_20190829_18_15_10.bin';
I have no idea about your folder structure, but Im guessing its 'Figures\t_20190829_18_15_10' ? If so, you would need to write
mkdir(['Figures\', fname(11:end-4)]);
and the same as the argument for 'exist'
5 Comments
Stephen23
on 29 Aug 2019
"..but how should it look like with my code."
See my answer.
It uses more robust fileparts rather than fragile indexing.
It uses simple fullfile to join the folder and file names.
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