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Anomalous histogram for small argument
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Gordon Edwards
on 6 Sep 2019
Commented: Gordon Edwards
on 7 Sep 2019
Running the following code from the command line with c = 1e-15 or greater leads to a normal histogram
c = 1e-15; figure; histogram(c * rand(100,1))
![histogram1.JPG](https://www.mathworks.com/matlabcentral/answers/uploaded_files/237214/histogram1.jpeg)
Running the following code with c = 1e-16 or less leads to an incorrect histogram
c = 1e-16; figure; histogram(c * rand(100,1))
![histogram2.JPG](https://www.mathworks.com/matlabcentral/answers/uploaded_files/237215/histogram2.jpeg)
The problem appears also in apps when the histogram function is invoked.
Is this a bug?
Gordon
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Accepted Answer
Bruno Luong
on 7 Sep 2019
Edited: Bruno Luong
on 7 Sep 2019
Yes it is a BUG. I chase back and in the file
C:\Program Files\MATLAB\R2019a\toolbox\matlab\datafun\+matlab\+internal\+math\binpicker.m
line #20 (R2019a)
there is a test
if xrange > max(sqrt(eps(xscale)), realmin(class(xscale)))
To me the correct test should be (without sqrt)
if xrange > max(eps(xscale), realmin(class(xscale)))
Now if I change this line and rerun the code
c = 1e-16; figure; histogram(c * rand(100,1))
it produces correct plot
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/237290/image.png)
More seriously, the function binpicker is called by HISTCOUNT. So HISTCOUNT is also buggy. Not only plotting but calculation might be wrong.
More Answers (1)
Jackson Burns
on 7 Sep 2019
Here's a similar question asked a few years ago which was never really solved either. This comment may be your best approach, but I would reccomend just bringing the values to unity with something like this:
c = 1E-16;
figure
mydata = c * rand(100,1);
histogram(mydata./max(mydata))
You could then modify the xticklabels to match whatever the original values were.
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