Array indices must be positive integers or logical values.

5 views (last 30 days)
I am getting above error.
data_out(i,1:dtn)=data_in_temp(colum-dtn+1):colum)
where dataout =1586*128 double
row=1586;
colum=128
dtn=129;
data_in_temp=1*128
  4 Comments
Bjorn Gustavsson
Bjorn Gustavsson on 9 Sep 2019
colum-dtn+1
should become 0 with the values you've given, matlab uses 1-based indexing, so your indices has to be larger than zero. Possibly your left-hand-side index i is also unallowed, but if you've set that one to a positive integer then it's OK (I've stopped use i and j as indices - sooner or later one tend to use them for their purpose of the imaginary 1i. Instead I use i1, i2 and j1 etc for simple loop-variables, that saves me from occasional but very irritating bugs and errors.)
HTH
Fabio Freschi
Fabio Freschi on 9 Sep 2019
true, but the error pointed out by the OP is about wrong indexing

Sign in to comment.

Answers (2)

Stephen23
Stephen23 on 9 Sep 2019
Edited: Stephen23 on 9 Sep 2019
Check your indexing:
>> colum = 128;
>> dtn = 129;
>> colum-dtn+1
ans = 0
MATLAB indexing start at 1.

TADA
TADA on 9 Sep 2019
in Matlab, matrix indices start from one, not zero like other programming languages, but your index starts from zero:
colum-dtn+1 = 0
so what you are actually doing is this:
data_out(i,1:129)=data_in_temp(0:128)
I guess what you did try to do is more like copy the entire row of data_in_temp into the i'th row of data_out?
if so, try this:
data_out(i,:) = data_in_temp
or if you are trying to copy a subset of that row, make sure the index of data_in_temp is the same size as that of data_out

Categories

Find more on Resizing and Reshaping Matrices in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!