How to specify a number to the specified position in the array？

Hi guys, the question is that now I used 'zeros' command, to create an array which have 20 positions, then there are some data will be created to fill the array, and I want to point data to the specified position. For example, the No.1 data should stay in the first position, the end data should stay in the second position, the No.2 data should stay in the third position. Is there any function can help me arrange their positions? Thanks a lot !

Answer 1

[Andrei Bobrov]

a = [2 3 5 7 11];

out = [a;flip(a,2)];
out = out(1:numel(a));

Answer 2

[the cyclist]

There's probably not an built-in function that does just that, but it's easy to do it with basic array manipulations. Here is one way.

newData = 1:20; % Your example "new" data
newNewData = [newData(1:10); newData(20:-1:11)]; % Make even newer data, temporarily in 2-d array
newNewData = newNewData(:)' % Make the newer data into a row array

[YANGCHENG LIUL]

Many thanks firstly, I tried this command just now, I found it cannot find the mid position if the range is nor sure, and the data is random...

[the cyclist]

Did you try to understand what my code is doing, or just blindly copy it?

My code works for the case you wrote in your question. If you need it to be more general, you should write your question in a way that describes the general case.

[YANGCHENG LIUL]

yes I understand it, separate it to 2 rows in different order, then mix them together, but my data is not just from 1 to 20, usually they are random. I think maybe it can solve by cell function

[the cyclist]

When you say "random", do you mean the length of the vector is random? Or that the values in the vector are random?

If your data is

[2 3 5 7 11]

what would you want the output to be?

[YANGCHENG LIUL]

random length of vector and random data, it is a length calculation function, the number of variable maybe 10, 15, or 20, and the value is random too. As you gaved example, I want the data can be arranged as [2 11 3 7 5].