matlab code running problem

1 view (last 30 days)
aniruddh mali
aniruddh mali on 24 Sep 2012
I am trying to run following code on matlab 7.7.0 but it consumes too much time and No output !
for i=1:length(data);
if y1(i)>1.2
it also can not be run on matlab 6 though the developer said that it works on matlab 6.
Jan on 24 Sep 2012
Why do you claim that this piece of code does not run under Matlab 6?

Sign in to comment.

Answers (2)

Jan on 24 Sep 2012
Edited: Jan on 24 Sep 2012
It is not clear what your code should do. Creating "1:length(data)" in each iteration is a waste of time. In addition you overwrite the elements of f most likely.
Did you forget a "for" before "j=..."?
What do you want to achieve?

Javier on 24 Sep 2012
Hello Mali
What is the purpose of this code ??? Does the variable j change size in each iteration ? If not, do not define it. I believe that you define "j" to establish the size of f. Something that could work better:
j=size(data,1) % for column vector
If want to find the elements in y1 that are greater than 1.2
[r,c,i]=find(y1>1.2); Now you have the row, column and index value that match the search
Now you have the data, What you want to do with them ???
Hope it helps


Find more on Debugging and Analysis in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!