Read text file with multiple rows of fields

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I am trying to read in a large text file with a challenging formatting. Instead of one long row of many fields, the file is broken into chunks with multiple rows of fields. Additionally, the headers repeat every so often and at an inconsistent rate. I've attached an example. I am trying to find a way to efficiently read in the data and organize it so that each field is a single array in a struct/cell/table/etc. The best I can think of is just to go line by line, knowing how many rows are in each block, and detect when I've encountered headers.

Accepted Answer

Jeremy Hughes
Jeremy Hughes on 22 Nov 2019
The current best way I know how to do this is with TEXTSCAN.
fmt = "%s%s%s%s%*[^\r\n]%*[\r\n]%s%s%s%s"
fid = fopen('sampleFile.txt')
data = textscan(fid,fmt,1,'Delimiter','\t','HeaderLines',5) % will read two lines at a time.
data = textscan(fid,fmt,1,'Delimiter','\t') % after header
This is just a starting point, you'll have to do some work based on the results you're looking for in the file.
  2 Comments
David K
David K on 22 Nov 2019
This is great, thank you! I didn't realize you could include line breaks like that. What is the purpose of the %*[^\r\n] in your formatSpec? Just to catch any extra characters at the end that might show up? I tried it without and it seemed to work fine.
Jeremy Hughes
Jeremy Hughes on 22 Nov 2019
That's absolutly right. %*[^\r\n]%*[\r\n] skips up to the next instance of \r or \n, then skipping all the following \r or \n characters. It's a neat trick for consuming lines.

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