# Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 2-by-2.

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Areg Arzoomanian on 25 Nov 2019
Edited: the cyclist on 25 Nov 2019
for i=1:n
for j=1:n
c(i,j)=(Yv(i)./(((Yv(i).^2)-(Yc(j).^2))))*(1/(2*pi))
end
end
for i=1:n
for j=i:n
if i>=j
k(i,j)=1
else i<j
k(i,j)=0
end
end
end
for j=1:n
B(i)=(0.5*0.25*5.7296*0.1222)
end
for i=1:1:n
for j=1:1:n
A(i,j)=(0.5)*(c)*(Cla).*(C(i,j))+k(i,j)
gamma(i)=B(j)./A(i,j)
wj=(C(i,j).*gamma(i))
end
Why is this coming up and how do i fix it, Im not sure where it's going wrong

#### 1 Comment

the cyclist on 25 Nov 2019
Not related to the error you are getting, but this section
for j=1:n
B(i)=(0.5*0.25*5.7296*0.1222)
end
is strange to me, since it is a loop over j, but you are indexing into B with the variable i.

the cyclist on 25 Nov 2019
In the line of code giving the error:
A(i,j)=(0.5)*(c)*(Cla).*(C(i,j))+k(i,j)
you are using the full matrix c. Maybe you wanted c(i,j) there?
You don't show what Cla is, but possibly the same problem there?

Areg Arzoomanian on 25 Nov 2019
c and Cla are constants, with values of 0.25 and 5.7296 respectively. I dont see how that can effect my answer
Areg Arzoomanian on 25 Nov 2019
now i get 'Index in position 2 exceeds array bounds (must not exceed 1).'
the cyclist on 25 Nov 2019
c is not a constant, because of the following code you show:
for i=1:n
for j=1:n
c(i,j)=(Yv(i)./(((Yv(i).^2)-(Yc(j).^2))))*(1/(2*pi))
end
end
It looks like maybe you mixed up some lower- and upper-case variables? MATLAB is case-sensitive.

R2018b

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