challenge implementing for loop

I have chanllenges implementing this code to run a loop from Tmax to Tmin and accepting or rejecting m based on if statement

theta = [0:90]';

M = [1800;400;1850;0.2;0.5]';

Dm = ref_coeff(M,theta);

Ds = Dm + (0.02*randn(size(Dm)) + 0);

T = [logspace(3,0)]';

Mint = M;

for T = max(T) : min(T)

Er = (abs(Ds - Dm))./(0.02);

E = sum(Er);

n1 = 25 .* randn(1,1) + 1800

m1 = 1500 + n1*(2000 - 1500)

n2 = 50 .* randn(1,1) + 400

m2 = 0 + n2*(1000 - 0)

n3 = 50 .* randn(1,1) + 1850

m3 = 1200 + n3*(2200 - 1200)

n4 = 0.05 .* randn(1,1) + 0.2

m4 = 0 + n4*(1 - 0)

n5 = 0.05 .* randn(1,1) + 0.5

m5 = 0 + n5*(1 - 0)

m = [m1;m2;m3;m4;m5]'

dm = ref_coeff(m,theta)

ds = dm + (0.02*randn(size(dm)) + 0)

En1 = (abs(ds - dm))./(0.02)

En = sum(En1)

Ec = En - E

if Ec(T) >= 0

fprintf('%d.\n',m)

elseif (exp(Ec(T)/T)) > randn(0,1)

fprintf('%d.\n',m)

end

end

[KALYAN ACHARJYA]

 Er=(abs(Ds - Dm))./(0.02);
  E = sum(Er);
  n1 = 25 .* randn(1,1) + 1800
  m1 = 1500 + n1*(2000 - 1500)
  n2 = 50 .* randn(1,1) + 400
  m2 = 0 + n2*(1000 - 0) 
  n3 = 50 .* randn(1,1) + 1850
  m3 = 1200 + n3*(2200 - 1200)
  n4 = 0.05 .* randn(1,1) + 0.2
  m4 = 0 + n4*(1 - 0)
  n5 = 0.05 .* randn(1,1) + 0.5
  m5 = 0 + n5*(1 - 0)
  m = [m1;m2;m3;m4;m5]'
  dm = ref_coeff(m,theta)
  ds = dm + (0.02*randn(size(dm)) + 0)
  En1 = (abs(ds - dm))./(0.02)
  En = sum(En1)
  Ec = En - E

These expressions are independent with T, still why you are keeping those assignment within for loop with the variation of T?

You can use the proper indexing, likewise

T=sort(T);
Mint=M;
for i=1:length(T)
if T(i)...
     .........
end
end