# Interval where values are greater than treshold

2 views (last 30 days)
Lucas Russi on 10 Dec 2019
Commented: Lucas Russi on 10 Dec 2019
Hi everyone
Logic = Data > Treshold
I now need to know what the intervals are where the treshold is exceeded
Logic = [1 1 1 0 0 0 1 1 0 1]
Desired_Output = [1 3;7 8;10 10]
So - from 1 to 3, from 7 to 8 aswell as 10
I can't think of a good way to do this.

Stephen Cobeldick on 10 Dec 2019
>> B = find([true;diff(Logic(:))>0]);
>> E = find([diff(Logic(:))<0;true]);
>> M = [B,E]
M =
1 3
7 8
10 10

#### 1 Comment

Lucas Russi on 10 Dec 2019
gracias <3

Jeremy Marcyoniak on 10 Dec 2019
I believe you are looking for the find command.
find(Logic)

Lucas Russi on 10 Dec 2019
find(Logic) = [1 2 3 7 8 10]
not exactly - I'm aware of find; there's one more step to get to what I put as my desired Output .. and there's the issue
Jeremy Marcyoniak on 10 Dec 2019
You could use
diff
to determine adjacent numbers and drop the intermediate numbers appropriately
Lucas Russi on 10 Dec 2019
Thanks for participating :)
idx = find(Logic)
idx(end+1) = 0
idx(diff(idx) ~= 1)
would be the indices that mark the end of the interval - but what about the start ?