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z=xtanθを求めたい

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Ryosuke KIJIMA
Ryosuke KIJIMA on 27 Jan 2020
Answered: Ryosuke KIJIMA on 27 Jan 2020
θ=30°
x=600
の時のzを求める式を教えてください。

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Accepted Answer

T.Tomita
T.Tomita on 27 Jan 2020
Edited: T.Tomita on 27 Jan 2020
こんなかんじでしょうか.
theta = 30*pi/180;
x = 600;
z = x*tan(theta)

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Ryosuke KIJIMA
Ryosuke KIJIMA on 27 Jan 2020
できました! ありがとうございます!

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