MATLAB Answers

How to replace a rectangle with another rectangle?

5 views (last 30 days)
Kirsten Moons
Kirsten Moons on 29 Jan 2020
Edited: Ridwan Alam on 30 Jan 2020
(Or change the properties of the first rectangle)
I had 2 ideas of how to replace the rectangle, but both don't work. But here they are:
Idea 1:
r = findobj('FaceColor', [0.2 0.2 0.7])
r.FaceColor = [0.2 0.2 0.2]
Idea 2:
r = rectangle(findobj('FaceColor', [0.2 0.2 0.7]))
r.FaceColor = [0.2 0.2 0.2]
Idea 3:
r = findobj('FaceColor', [0.2 0.2 0.7])
rectangle('Position',r.Position,'LineWidth',1, 'FaceColor', [0.2 0.2 0.7])
I think you can't story a rectangle in a variable but I'm not sure and don't know how to do it otherwise. I want to change the facecolor of the rectangle with the facecolor [0.2 0.2 0.7].

  2 Comments

Walter Roberson
Walter Roberson on 30 Jan 2020
The form in Idea 1 worked when I tried it, if the goal is to change the color of an existing rectangle without creating a new one.
Kirsten Moons
Kirsten Moons on 30 Jan 2020
Okay, thank you for your feedback. Then I don't know why it doesn't work for me.

Sign in to comment.

Answers (1)

Ridwan Alam
Ridwan Alam on 30 Jan 2020
Edited: Ridwan Alam on 30 Jan 2020
I tried this, it worked for me:
r = rectangle('FaceColor', [0.2 0.2 0.7]);
r.FaceColor = [0.2 0.2 0.2];

  2 Comments

Kirsten Moons
Kirsten Moons on 30 Jan 2020
I dont know the position of the rectangle, thats why I use findobj.
Ridwan Alam
Ridwan Alam on 30 Jan 2020
Even this worked:
r = rectangle('FaceColor', [0.2 0.2 0.7]); % created the rectangle
r1 = findobj('FaceColor', [0.2 0.2 0.7]); % finds the rectangle handle
r1.FaceColor = [0.2 0.2 0.2]; % change rectangle property using handle
Please let me know which part is not working for you.
Btw, if the rectangle doesn't exist, findobj() returns an empty handle.

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!