storing fprintf as an array.

The outcome of the code below gives H T H T T depending on random function. How do I store the outcome of the 20 iterations into  a variable called 'product' ; for example: product =[ H T H T T......] so that whenever I need it, I can fetch the outcome by just typing 'product' 
fprintf('The Outcomes are:\n')
for i = 1:20
       A =  rand(i,1);
       if A(i) >= 0.5000
       fprintf('%s\n', 'H');
       else
       fprintf('%s\n', 'T');
       end
end

Answer 1

[David Hill]

Why do a loop?

product=rand(1,20);
product(product>=.5)=72;
product(product<.5)=84;
product=char(product);

[Jide Williams]

Thanks, i needed the for loop because I want to perform a Monte Carlo Analysis. This is better in loops

Answer 2

[Walter Roberson]

Outcome(i) = 'H';

The closest to your current code would be

Outcome{i} = sprintf('%s\n', 'H') ;

[Jide Williams]

Thanks, and yes, I did that but my result is weird. One would expect a 'H' if A >= 0.5 but it returned a tail T, so I felt maybe that isnt right!

[Jide Williams]

for example for the first three outcomes A =

0.0765

0.7809

0.1307

Outcome should be (T H T), right? But it returned: (T H H)

[Walter Roberson]

No. You call

A = rand(i, 1)n

That defines A to be a column vector of random numbers with i values in the vector. In the next line you access A(i) which is only the last of those values and not any of the values before that. But when you are examining to see whether the code works, you are reading off the first of the values, not the last. Or perhaps after the loop you are examining A, but since you overwrite all of A each time, the values that were used to make the decision have been thrown away and replaced by new values before you look.

Your code should be:

A(i) = rand(1,1);

[Jide Williams]

Yeah i have seen my mistakes. Thans