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Data comparison and storing

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Zeus
Zeus on 28 Mar 2020
Closed: MATLAB Answer Bot on 20 Aug 2021
I've created a sensor to take readings daily .
Humidity =
20×1 string array
"34.099045"
"42.425098"
"33.480418"
"35.790796"
"30.370059"
"44.029928"
"49.041827"
"44.980187"
"45.134548"
"40.841782"
<missing>
<missing>
<missing>
<missing>
<missing>
<missing>
<missing>
<missing>
<missing>
<missing>
HumidityTime =
2 24
4 48
7 12
9 36
12 0
14 24
16 48
19 12
21 36
24 0
  5 Comments
Peng Li
Peng Li on 29 Mar 2020
Again you have 20 rows in humidity data but 10 rows in humidity time. How do they match? If they match by rows, you can use HumidityTime(double(humidity) > 40 & double(humidity) < 50, :) to get the times that humidity meet your defined criterion.
Zeus
Zeus on 29 Mar 2020
so i managed to get them to be equal ,I got rid of the excess <missing> terms by changing my data collection code.
I have tried ur suggestion HumidityTime(double(humidity) > 40 & double(humidity) < 50 and it is not working .Please suggest an alternative
Humidity =
46.8068
42.5006
35.1041
48.0938
45.3460
41.2533
47.9431
37.3616
36.7546
42.3771
HumidityTime =
2 24
4 48
7 12
9 36
12 0
14 24
16 48
19 12
21 36
24 0

Answers (1)

Mohammad Sami
Mohammad Sami on 30 Mar 2020
Humidity = str2double(Humidity(~ismissing(Humiditiy)));
lowlimit = 40;
highlimit = 50;
outsidelimit = Humidity > highlimit || Humidity < lowlimit;
alerts = [HumidityTime(outsidelimit,:) Humidity(outsidelimit)];
  2 Comments
Zeus
Zeus on 19 Apr 2020
it gives me this when i run .i need to have nx3 matrix in output (hours minutes Humidity)
Humidity =
NaN
outsidelimit =
logical
0
alerts =
0×2 empty double matrix
Walter Roberson
Walter Roberson on 20 Apr 2020
At the time you get that output, what is the string array that you are starting with ?

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